0=-16x^2+64x+96

Solution for 0=-16x^2+64x+96 equation:

0=-16x^2+64x+96

We move all terms to the left:

0-(-16x^2+64x+96)=0

We add all the numbers together, and all the variables

-(-16x^2+64x+96)=0

We get rid of parentheses

16x^2-64x-96=0

a = 16; b = -64; c = -96;
Δ = b2-4ac
Δ = -642-4·16·(-96)
Δ = 10240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10240}=\sqrt{1024*10}=\sqrt{1024}*\sqrt{10}=32\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-32\sqrt{10}}{2*16}=\frac{64-32\sqrt{10}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+32\sqrt{10}}{2*16}=\frac{64+32\sqrt{10}}{32}
$